When interviewing for an electrical engineering position, it is important to be prepared with the right knowledge and skills. Understanding the basics of RC circuits is an essential part of being a successful engineer, and being able to answer interview questions related to RC circuits can make all the difference in your job search. In this blog post, we will discuss some of the most common RC circuits interview questions and provide tips on how to best answer them. We will go through some of the basic principles of RC circuits and explore the different types of questions that interviewers may ask during the interview process. Whether you are a recent graduate or experienced engineer, you will find this blog post helpful in preparing for your interview.
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VISIT HERE Click for the solutions Compare the output characteristics of transistor BJT (Bipolar Junction Transistor) and FET (Field Effect Transistor) and also mark the different regions of operations on the characteristics.2. Given the following RC circuit. Plot the output waveform for the given input based on the given two conditions.
3. With regard to the particular DAC (Digital to Analog Circuit) circuit depicted in the figure Vout should be calculated for the digital input D3D2D1D0 = 1010. if Vref =8V.
4. Determine the minimum voltage Vx at which the resistor R’s maximum current flows. Assume Vth = 400mV and µnCox = 250.
5. Determine the voltage Vout value for the given circuit. What is the possible application of this circuit?.
6. Draw the output waveforms VA and VB for the specified square wave input in the circuit shown below. 7. Which of the circuits below has the higher output impedance, and why?
8. Find the voltage Vx for the below circuit. Given µnCox = 100 and Vth = 1V.
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In actuality, the current flowing to ground in R1 is produced by the junction between the charging current in C3 and the discharging current in C1. Each capacitor’s current is equal to C*dv/dt but flows in opposite directions. The current is equal to V/R at any time when the two currents are added, where V is the voltage across the resistor.
Positive charge must be added to the right side of C3 and to the top of C1 for C3 to discharge (voltage across it decreases) and C1 to charge (voltage across it increases). Additionally, R1 must source conventional current rather than sink it, which means that electron flow must occur from the positive terminal of the power supply to the negative terminal. No can do!.
The voltage across both capacitors would have to drop if you proposed adding the positive charge from the top of C1 to the right side of C3. The fact that they are connected to each other and require the same voltage at the connection point makes it impossible as well.
C1 will charge to a lower voltage than C3 when the input step voltage is applied. This is due to the requirement that the charging current of C3 equal the sum of the charging currents of C1 and R1. Therefore, C1 will charge slower than C3, which will result in a lower voltage across it after the step input than C3. Therefore, the voltage across C1 is lower than the voltage across C3 right after the step input if the charging current is lower and the dv/dt is lower.
At the intersection of the three components when the step input is applied, it basically follows Kirchoff’s current law, which states that the magnitude of the current supplied by the supply must equal the magnitude of the current returned.
Using Laplace and nodal analysis.
Let $small V(s)$ be the voltage at the C1/C3/R1 node. The input voltage step is $large frac{V_1}{s}$.
The node equation reads as follows: $$small left (V(s)-fracV_1sright)sC + V(s)sC+ fracV(s)R=0$$
Inverse Laplace transform: $$v(t)small =fracV_12e-t/2RC$$ Small V(s)=fracV_1 RC1+2RCs=fracV_1 /2sC+frac1Rright$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$
The node voltage therefore begins at a large fracV_1 and decays exponentially to zero with a time constant of small tau=2RC.
As a result, C3 has a “small V_1” across it at steady state, i e. there is 0 V on its right hand plate. There is therefore no need to top-up C1 because there is 0 V across C1 and 0 V across R.
Since both capacitors conceptually appear to be short circuits at time zero, a significant instantaneous current flows into each one, charging it to a voltage of $fracV_12$. These two voltages are combined in series to balance the applied voltage step.
My response focuses on a slightly different “real” argument for aid. In fact, it cant charge . because it is “discharging” . See the C1 current. I created a simulation in which I added some serial resistors with low values to the capacitors. (NB: if not, the currents are “infinite” . and the @Chu answer apply).
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FAQ
What are RC circuits used for?
Capacitors and resistors are frequently found in RC circuits. Such RC circuits are common in everyday life. They regulate many different electronic devices, including heart pacemakers, camera flashes, and the speed of a car’s windshield wipers and the timing of traffic lights.
What is the principle of RC circuit?
A resistor-capacitor circuit (RC Circuit) is a type of electrical circuit that uses capacitors and resistors as passive components and is powered by either a voltage source or a current source. The resistor connected to the circuit regulates the rate of charging or discharging, and the capacitor stores energy.
How do you solve RC circuit problems?
Finding the current across R2 after time t in a complex RC circuit that has been excited by DC Currently, the voltage across the capacitor is V(0)=0 initially and stays the same during switching. This is the same as the voltage across R2. The capacitor is fully charged and acts as an open circuit in steady state.
Is RC circuit leading or lagging?
The power factor of the RL circuit is lagging, i. e. , the circuit current lags the supply voltage. The RC circuit’s power factor is leading, which means that the supply voltage leads the circuit current.
