Top 50 IP addressing interview questions and answers

Network Interview Questions Series Part-2 (Subnetting)

A bitwise AND operation is used in networking to compare two binary values and return a new value that is the result of the AND operation. The AND operation will return a 1 if both values being compared are 1, and will return a 0 if either value is a 0.

Subnet masks are used in networking in order to help identify which network a particular device is on. By looking at the subnet mask, a network device can tell which part of the IP address is the network address and which part is the host address. This information is then used to route traffic appropriately.

Subnetting can be used in a number of different ways, but one of the most common is in the creation of virtual private networks (VPNs). When you create a VPN, you are essentially creating a private network that is isolated from the rest of the internet. By subnetting the network, you can further isolate different parts of the network, which can be useful for security purposes. Additionally, subnetting can be used to improve network performance by segmenting traffic.

A default gateway is the node in a computer network that acts as an access point to another network. A default gateway is often a router that connects a local network to the Internet. When a computer is connected to the Internet, the computer will send all of its traffic to the default gateway unless it is specifically directed to another address.

NAT is short for Network Address Translation. It is a technology most commonly used by firewalls and routers to allow multiple devices on a private network to share a single public IP address. NAT can also be used to map different private IP addresses to different public IP addresses, depending on the configuration.

ifconfig(interface configuration) command is used to configure the kernel-resident network interfaces. It is used at boot time to set up the interfaces as necessary. After that, it is usually used when needed during debugging or when you need system tuning. Also, this command is used to assign the IP address and netmask to an interface or to enable or disable a given interface. For more details, please refer to

DHCP is an abbreviation for Dynamic Host Configuration Protocol. It is an application layer protocol used by hosts for obtaining network setup information. The DHCP is controlled by a DHCP server that dynamically distributes network configuration parameters such as IP addresses, subnet mask, and gateway address. For more details, please refer to Dynamic Host Configuration Protocol (DHCP) article.

MAC Addresses are unique 48-bit hardware numbers of computers, which are embedded into a network card (known as Network Interface Card) during the time of manufacturing. The MAC Address is also known as the Physical Address of a network device. In IEEE 802 standard, the Data Link Layer is divided into two sublayers –

A maximum transmission unit also called MTU, is a term used in networking and operating systems. It defines the largest size of the packet that can be transmitted as a single entity in a network connection. The size of the MTU dictates the amount of data that can be transmitted in bytes over a network. For more details, please refer What is MTU article.

28. What happens in classless addressing, if there are no classes but addresses are still granted?

Interview Questions for CCNA | Subnetting | Supernetting

  • By
  • August 28, 2019
  • CCNANetworking
  • Hello readers, welcome back to my Networking Interview Questions Blog series. In this blog series from CCNA Course in Pune, in the last blog, I covered Basic Networking Interview questions and answers. Now, this time I am going to cover questions and answers with explanation on Subnetting and Supernetting. According to most of the newcomers, Subnetting is the most difficult concept in CCNA. For me, Subnetting is my favorite topic and I believe anyone who can do basic arithmetic can easily learn Subnetting and score good marks in CCNA with the help of CCNA Classes in Pune as it is one of the simplest topics. The questions are always somewhat confusing but interesting at the same time.

    Let’s first see what is Subnetting and why it is needed? Everyone loves technology, and technology heavily relies on Networking. Everybody from a Social media user to an Economist, Doctors to Engineers, Artists to Developers use the internet or some other form of a network for their day to day use. So the network is everywhere nowadays. But as network size increases, it becomes very complex to manage it and to keep it secure. The performance of the network also decreases as its size increases. So a large network is divided into smaller networks, they are called Subnets, which are easier to manage and they are more secure as well. As they divide the broadcast domain, network performance also increases. So big organizations, divide their network into Subnets as per their requirements like for branches or departments.

    So, now what is Supernetting and where it is used? Supernetting is just opposite to Subnetting, that means adding contiguous Subnets into a single network is called Supernetting. But, for our ease, we divide a big network into Subnets, then why Supernetting is required? The answer is, we never use Supernetting. In fact, Routers use Supernetting to reduce the size of their respective routing tables, which in turn facilitates faster routing performance and reduces the latency of routed traffic. Hence the other terms used for Supernetting are Route Summarization or Aggregation.

    Now you have an idea about what is Subnetting and Supernetting. So let’s start solving questions based on Subnetting and Supernetting which you can expect in Networking Interviews. Please note: I have mentioned questions with their respective answers as well as explanations so that everyone gets to know the correct way to do the Subnetting and Supernetting calculations.

    Q>1] When calculating the maximum available valid host addresses in each subnet, why we always minus 2 addresses from total addresses?

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    Ans:] The 2 addresses are Network Address and Broadcast Address.

    Every IP address of any Network or Subnet should have one unique ID to identify the other hosts on the same network or subnet. This unique ID is known as Network address, which is also used by Router to mention in its Routing Table. This Network address is common for all the hosts in the network, hence we cannot assign or configure it to any single node. The Network address is the address where all the Host bits are “0”.

    Every Network or Subnet has one more IP address common for all its host, which is known as Broadcast address. Broadcast is one to all type of communication. That means this address is used as the destination address in the Packet when any host wants to send a message to all other hosts on the same network. This broadcast address is the same for all the hosts in the network, hence we cannot assign or configure it to any single node. The Broadcast address is the address where all the Hosts bits are “1”.

    Q>2] How many subnets and maximum hosts per subnet can we get from the subnet network 172.27.0.0/23?

    Ans:] Subnets: 128, Maximum Hosts / Subnet: 510

    Explanation:] IP Address: 172.27.0.0 is from Class ‘B’ that is default network bits are 16 and Host bits are 16.

    For /23, Borrow bits will be: 23 – 16 = 7

    Hence, Number of Subnets = 27 = 128

    For /23, Host bits will be: 32 – 23 = 9

    Hence, Maximum Hosts in each Subnet = 2H – 2

    = 29 – 2 = 512 – 2 = 510

    Q>3] Subnet the Network 203.10.93.0/24 into 25 Subnets. After Subnetting, is IP 203.10.93.30 a valid Host ID?

    Ans:] YES

    Explanation: For 25 Subnets, we need to borrow 5 bits, as 25 = 32 > 25

    Hence, now Network Bits will be: 24 + 5 = 29 Hence Subnetting CIDR is: /29

    Subnet Mask ? /29 = 255.255.255.248

    Therefore, Subnetwork Block Size = 256 – 248 = 8

    Hence, Subnetworks are designed as bellow

    NW Address 1st Host Last Host Broadcast Address
    203.10.93.0 203.10.93.1 203.10.93.6 203.10.93.7
    203.10.93.8 203.10.93.9 203.10.93.14 203.10.93.15
    203.10.93.16 203.10.93.17 203.10.93.22 203.10.93.23
    203.10.93.24 203.10.93.25 203.10.93.30 203.10.93.31
    203.10.93.32 203.10.93.33 203.10.93.38 203.10.93.39
    And so on…….

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    As per the above table, it is clear that IP 203.10.93.30 is a valid Host ID.

    Q>4] Your company has been using the network of 193.56.7.0 /24. You want to put each of the 6 floors in your building on a different subnet. What is the range of the last available subnet after doing Subnetting?

  • 193.56.7.248 – 193.56.7.255
  • 193.56.7.32 – 193.56.7.64
  • 193.56.7.224 – 193.56.7.255
  • 193.56.7.240 – 193.56.7.255
  • Ans:] C. 193.56.7.224 – 193.56.7.255

    Explanation: For 6 Subnets, we need to borrow 3 bits, as 23 = 8 > 6

    Hence, now Network Bits will be: 24 + 3 = 27 Hence Subnetting CIDR is: /27

    Subnet Mask ? /27 = 255.255.255.224

    Therefore, Subnetwork Block Size = 256 – 224 = 32

    Hence, Subnetworks are designed as bellow

    NW Address 1st Host Last Host Broadcast Address
    193.56.7.0 193.56.7.1 193.56.7.30 193.56.7.31
    193.56.7.32 193.56.7.33 193.56.7.62 193.56.7.63
    193.56.7.64 193.56.7.65 193.56.7.94 193.56.7.95
    193.56.7.96 193.56.7.97 193.56.7.126 193.56.7.127
    193.56.7.128 193.56.7.129 193.56.7.158 193.56.7.159
    193.56.7.160 193.56.7.161 193.56.7.190 193.56.7.191
    193.56.7.192 193.56.7.193 193.56.7.222 193.56.7.223
    193.56.7.224 193.56.7.225 193.56.7.254 193.56.7.255

    As per the above table, Last Subnet range is 193.56.7.224 – 193.56.7.255.

    Q>5] Is below-given IP address is valid or not and give the reason for the same:

  • Yes Valid IP, as it is first hosting IP address of network 17.25.39.126/26.
  • Yes Valid IP, as it is the last host IP address of network 17.25.39.64/26.
  • No Valid IP, as it is the network address of network 17.25.39.127/26.
  • No Valid IP, as it is broadcast address of network 17.25.39.64/26.
  • Ans:] D. No Valid IP, as it is broadcast address of network 17.25.39.64/26.

    Subnet Mask ? /26 = 255.255.255.192

    Therefore, Subnetwork Block Size = 256 – 192 = 64

    Hence, Subnetworks are designed as bellow

    NW Address 1st Host Last Host Broadcast Address
    17.25.39.0 17.25.39.1 17.25.39.62 17.25.39.63
    17.25.39.64 17.25.39.65 17.25.39.126 17.25.39.127
    17.25.39.128 17.25.39.129 17.25.39.190 17.25.39.191

    As per the above table, 17.25.39.127 is a broadcast address of network 17.25.39.64/26.

    Q>6] You work in an enterprise, where 150.17.0.0/16 network is used. This network has divided into 450 subnets. In one office, you need to configure 10th valid IP address of 14th subnet to your router interface. What will be that IP address?

  • 150.17.13.10
  • 150.17.6.138
  • 150.17.5.10
  • 150.17.7.138
  • Ans:] B. 150.17.6.138

    Explanation: For 450 Subnets, we need to borrow 9 bits, as 29 = 512 > 450

    Hence, now Network Bits will be: 16 + 9 = 25 Hence Subnetting CIDR is: /25

    Subnet Mask ? /25 = 255.255.255.128

    Therefore, Subnetwork Block Size ?

    For 4th Octet, 256 – 128 = 128 and for 3rd Octet, 256 – 255 = 1

    Hence, Subnetworks are designed as bellow

    150.17.0.0, 150.17.0.128, 150.17.1.0, 150.17.1.128, 150.17.2.0, 150.17.2.128, 150.17.3.0, 150.17.3.128, 150.17.4.0, 150.17.4.128, 150.17.5.0, 150.17.1.0, 150.17.6.0, 150.17.6.128

    Hence the 14th Subnet Address is 150.17.6.128/25 and 10th valid IP address from this subnet is – 150.17.6.138.

    Q>7] What is the best summary network address for the following subnets:

    Ans:] 192.168.0.0/21

    Explanation: We are interested in the third octet because that’s where the values start to differ. Then focus on the third octet and convert it into the binary.

    1 ? 00000001

    2 ? 00000010

    3 ? 00000011

    4 ? 00000100

    Here we can see that the first 5 bits (left to right) are matching in all 4 numbers.Then, for the subnet mask, we add these bits from the third octet to the first two octets which are 16. So your Network bits will be ? 16 + 5 = 21 i.e. CIDR = /21

    The network Block size for the third octet is, 256 – 248 = 8

    Hence the Valid Network addresses will be:

    192.168.0.0, 192.168.8.0, 192.168.16.0, and so on.

    The answer, therefore, is 192.168.0.0/21

    Which encompasses the block of networks you need to be summarized.

    192.168.0.0 – 192.168.7.255 (Block size of 8)

    Q>8] You have a class ‘C’ network that needs 28 subnets while maximizing the number of valid host addresses available on each subnet. How many bits need to borrow from the host field to provide the correct combination, what will be the subnet mask and how many maximum valid hosts we will have in each subnet?

    Ans:] For 28 Subnets, we need to borrow 5 bits, as 25 = 32 > 28

    Hence, now Network Bits will be: 24 + 5 = 29 Hence Subnetting CIDR is: /29

    Subnet Mask ? /29 = 255.255.255.248

    Host Bits will be: 32 – 29 = 3

    Hence, maximum number of Valid host address = 23 – 2 = 8 – 2 = 6

    Q>9] A router has an interface with the IP address of 192.168.193.62/27 in your network. What are the IP addresses available which can you configure to a server in the same network?

    Ans:] 192.168.193.33 – 192.168.193.61

    Explanation: Subnet Mask ? /27 = 255.255.255.224

    Therefore, Subnetwork Block Size = 256 – 224 = 32

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    Hence, Subnetworks are designed as bellow

    NW Address 1st Host Last Host Broadcast Address
    192.168.193.0 192.168.193.1 192.168.193.30 192.168.193.31
    192.168.193.32 192.168.193.33 192.168.193.62 192.168.193.63
    192.168.193.64 192.168.193.65 192.168.193.94 192.168.193.95 & So on.

    So, as per the above table, the network address for given IP is 192.168.193.32 and broadcast IP is 192.168.193.63. The last valid IP is assigned to the Router that is Gateway. Hence available IPs are from 192.168.193.33 to 192.168.193.61.

    Q>10] One employee came to you and he was saying that the internet was not working on his system, but other employees could work on the internet. You went to his system and check its IP configuration and you saw 172.29.97.127/26 was configured there. What will be your first step to solve this problem?

    Ans:] The IP configured on the Employees system, 172.29.97.127/26 is Broadcast IP address. So firstly that IP needs to change.

    Explanation:] The Configured IP address: 172.29.97.127/26

    Hence, the Subnet Mask = 255.255.255.192

    The Network Block Size will be = 256 – 192 = 64

    Hence, Subnetworks are designed as bellow

    NW Address 1st Host Last Host Broadcast Address
    172.29.97.0 172.29.97.1 172.29.97.62 172.29.97.63
    172.29.97.64 172.29.97.65 172.29.97.126 172.29.97.127
    172.29.97.128 172.29.97.129 172.29.97.190 172.29.97.191
    172.29.97.192 172.29.97.193 172.29.97.254 172.29.97.255

    So, as per the above table, the network address for given IP is 172.29.97.64 and broadcast IP for that network is 172.29.97.127. We cannot configure Network address as well as the Broadcast address to any single node. As Network address is the unique identifier for all the nodes of the same network, which is used by Routers to mention best routes to every destination network in their respective Routing Tables. And Broadcast Address is used for broadcast communication that is one to all communication, which represents all the nodes in that respective network. So in the above problem, firstly we have change IP for that system and configure it in the range 172.29.97.65 to 172.29.97.126, which is a valid range for that particular network.

    Q>11] Which of the subnet masks we can use for a corporate network with 300 sub-networks and a maximum of 50 host addresses per subnet and working with only Class B address.

    ANS:] /25 = 255.255.255.128 and /26 = 255.255.255.192

    Explanation:] Given that we need to subnet class “B” network.

    Required Number of Subnets: 300

    And, Maximum of Host address per subnet is: 50

    To fulfill these requirements, we can use two combinations of NW bits and Host bits i.e. we can use 2 different Subnet Masks.

    Class “B”: Default Subnet Mask /16 = 255.255.0.0

  • For 300 Subnets we need to Borrow 9 bits such as, 29 = 512 > 300.
  • Hence, Network bits = 16 + 9 = 25

    Therefore, Host Bits = 32 – 25 = 7

    Maximum of Host address available = 27 – 2 = 126 > 50

    Means, both of the requirements are fulfil. So we can use CIDR /25 i.e. Subnet mask 255.255.255.128.

  • For 300 Subnets we need to Borrow 10 bits such as, 210 = 1024 > 300.
  • Hence, Network bits = 16 + 10 = 26

    Therefore, Host Bits = 32 – 26 = 6

    Maximum of Host address available = 26 – 2 = 64 > 50

    Means, both of the requirements are fulfil. So we can use CIDR /26 i.e. Subnet mask 255.255.255.192.

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    So, that’s it, guys. You can practice all the questions by just changing the numbers in the questions. Every question has given an answer with an explanation in which I show step by step calculations. So you can solve any type of question after changing the numbers also, as the steps for calculations are the same.

    And now, here is one extra bonus for you. I want to share an interesting shortcut with you, for solving any kind of Subnetting examples promptly and without any mistake. This shortcut is so simple that everyone can easily use it for all types of Subnetting as well as Supernetting examples. So, just go through the below video and you will get an idea for the same.

    https://youtu.be/yiWqEbJzgNE

    IP is the most interesting topic in the CCNA Training in Pune. And as you see in the above questions and answers, Subnetting and Supernetting are more engaging topics. Just you have to do some basic calculations and need logical and smart thinking for solving it fast.

    With this, I am concluding this blog. Will meet soon with a new part of this blog series which will include questions-answers on Routing and Routing Protocols.

    All the Best for your Bright future in Networking!!

    Author:- Sumaiyya Suhail Bagwan Department Name:- Networking Designation:- Technical Trainer

    Subnetting Practice with Subnetting questions

    In this Subnetting Practice Page, there are many Subnetting Questions that are always updated. With these excellent Subnetting Examples, you will find the change to practice different cases. These cases will also the cases that you will see in the real world scenarios. In other words, the Subnetting Questions in this Subnetting Quiz page, will show you many real world Subnetting Examples. Maybe, you will implement one of the cases to your own company’s network or you will be inspired from these examples. Whatever, you will benefit from this Subnetting Quiz page a lot!

    On many Certification Exams like Cisco CCNA, CCNP, CCIE Exams, Juniper JNCIA, JNCIS, JNCIP, JNCIE Exams, Huawei HCIA, HCIP, HCIE Exams, Nokia NRS I, NRS II, SRA Exams etc. there will be questions for Subnetting and you will use it. Before these exams, you should learn this lesson very well. If you would like to solve all the questions on Subnetting and the questions needs Subnetting, you can practice with the scenarios on this page. With these examples, you will be ready for all the network exams need Subnetting knowledge.

    FAQ

    What are the 5 classes in subnetting?

    One goal of a subnet is to split a large network into a grouping of smaller, interconnected networks to help minimize traffic. This way, traffic doesn’t have to flow through unnecessary routs, increasing network speeds. Subnetting, the segmentation of a network address space, improves address allocation efficiency.

    What are the rules of subnetting?

    There are five classes of subnetworks: Class A, Class B, Class C, Class D, and Class E. Each class relates to a specific range of IP addresses. Classes A, B, and C are used the most often by different networks.

    How do you solve subnet questions?

    It’s pretty straightforward: Every network or subnet has two reserved addresses that cannot be assigned to a host. The rule is that no host can have the IP address in which all the host bits are set to 0, and no host can have the IP address in which all the host bits are set to 1.

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